2 F.3 Question(Heat)－jpjzhf9的部落格

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2 F.3 Question(Heat)

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1) at 5 C, an uncalibrated thermometer reads 125 units. At 90 C, and it reads 500 units. Calculate the reading on this thermometer at the ice point and steam point.2)An experiment was carried out to calibrate an unmarked mercury-in-glass thermometer. The length of the mercury column when immersed in melting... 顯示更多 1) at 5 C, an uncalibrated thermometer reads 125 units. At 90 C, and it reads 500 units. Calculate the reading on this thermometer at the ice point and steam point. 2)An experiment was carried out to calibrate an unmarked mercury-in-glass thermometer. The length of the mercury column when immersed in melting ice and boiling water were 4.5 cm and 22 cm respectively. What was the temperature of the warm water which mercury column was 11.5 cm ?

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1 , for such kind of question , you have to use the following formula ( T1 - T2 ) / ( L1 - L2 ) = ( T2 - T3 ) / ( L2 - L3 ) T1 = 5 , T2 = 90 L1 = 125 , L2 = 500 for ice point T3 = 0 , L3 = ? ( T1 - T2 ) / ( L1 - L2 ) = ( T2 - T3 ) / ( L2 - L3 ) ( 5 - 90 ) / ( 125 - 500 ) = ( 90 - 0 ) / ( 500 - L3 ) L3 = 77.94 unit for stram point T3 = 100 , L3 = ? ( T1 - T2 ) / ( L1 - L2 ) = ( T2 - T3 ) / ( L2 - L3 ) ( 5 - 90 ) / ( 125 - 500 ) = ( 90 - 100 ) / ( 500 - L3 ) L3 = 544.12 unit 2 , T1 = 0 , L1 = 4.5 T2 = 100 , L2 = 22 T3 = ? , L3 = 11.5 ( T1 - T2 ) / ( L1 - L2 ) = ( T2 - T3 ) / ( L2 - L3 ) ( 0 - 100 ) / ( 4.5 - 22 ) = ( 100 - T3 ) / ( 22 - 11.5 ) T3 = 40 degree celcius 2007-01-03 14:07:47 補充： for ice pointT3 = 0 , L3 = ?( T1 - T2 ) / ( L1 - L2 ) = ( T2 - T3 ) / ( L2 - L3 )( 5 - 90 ) / ( 125 - 500 ) = ( 90 - 0 ) / ( 500 - L3 )L3 = 102.94 unit

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